Solutions – Formula Sheet (XI)

For the Best Experience, View on Desktop/Laptop !

Only the people who have attempted the Question Formula Sheet are allowed to continue further. It’s a rule 🙂  !! 

For those, who have not attempted, Go and attempt now ! – Question Formula Sheet

Note : 
  • The Solution sheet contains all the answers for the Question Formula Sheet. But it has something more !
  • As discussed earlier, this sheet is actually a set of mini-problems. So, through this sheet, we have also tried to cover some methods/approaches to solve JEE or high school physics problems. 
  • These approaches can help you to get much more efficient ways to solve the problems !

Solution Sheet :

You can download the file from here – DOWNLOAD

Solutions - Formula Sheet (XI)

Formula Sheet – XI

For Best Experience, View on Desktop/Laptop !

The formula sheet is mainly designed for the high school physics students. This sheet would definitely help students to boost up their   JEE Mains preparation. 

Important Note : 
  • The Question Formula sheet is basically a set of mini-problems. This would help you to understand the use of the formulae as well
  • Keep solving the sheet atleast thrice a week. The more, the better. It will really help you in problem solving
  • Don’t refer to the solution sheet (attached separately below) directly. Use the solution sheet as your reference. You might find a shorter way to do the same thing !

Question Sheet :

Chapters Covered :
  • Kinematics
  • Laws of Motion
  • Work, Energy and Power
  • Rotational Motion
  • Gravitation
  • Fluid Mechanics
  • Thermodynamics
  • Kinetic theory of Gases (KTG)
  • Oscillations and Waves

Download the Question sheet file below by clicking here – DOWNLOAD

Formula Sheet - (XI)

Conclusion :

Use this formula sheet quite frequently. This work is inspired by my physics teacher. Be consistent in solving it !!

Solution Sheet has been uploaded !! (*Click only when the formula sheet is attempted*) – SOLUTION

Till then, Keep practicing !!

All the Best !!

String-Pulley Constraint Relations

String Pulley Constraints are very commonly used in high school physics and mainly comes under Newton’s Laws of motion (NLM). This concepts are frequently asked in exams such as JEE Mains and even JEE Advanced !! 

Time becomes an important factor in such competitive examinations, especially JEE Mains. So, it’s always better to have some short tricks to be faster and save time. But, still, I would like to emphasize on the fact that concept>>tricks


How to apply ?

Remember the rules :

  • Only one string at a time
  • On the string –> ‘minus’ sign (Recall the -ve charge sign on ions from chemical bonding because that’s how I kept it in my mind)
  • Away from the string –> ‘plus’ sign
How to use it in problems ? (Have patience…Lot of things are about to get easier for you)

Steps :

  1. Mark the points on the string such that whole string is covered (starting to end)
  2. For pulleys, mark for the points- where the string first comes in contact with the pulley (pt 2) and where the string leaves the contact with pulley (pt 3)
  3. Now start from one end,( say pt1) . The relation will be as follows (-Va + 0 + 0 +Vb) 

Why ?

-Va because Va is going on the string

+0 because pt2 is connected to pulley and pulley is at rest

+0 pt3 is connected to pulley and pulley is at rest

+Vb because pt4 is connected to block B and Vb is going away from the string

      4.  Finally equate everything to zero i.e. (-Va + 0 + 0 +Vb = 0)

Final Answer : We get Va  = Vb


Easy Examples

Q.1 Write down the constraint relation between velocities of block A and block B by referring the image of setup alongside.

Solution :

Constraint relation can be written as : (Applying trick, starting from block A)


Q.2 Write down the constraint relation between velocities of block A and block B by referring the image of setup alongside.

Solution :

We start from block A (Just move along the string one-by-one) :


Q.3 Write down the constraint relation between velocities of block A and block B by referring the image of setup alongside.

Solution : Let’s start from block A


Moderate to Difficult Examples

Solution : Part(a) –

 (Lets start from the point near the rigid support)

Part (b) :  Again we start from the point attached to the rigid end 

(Note that the derivative of velocity wrt time is acceleration. So once you get the velocity constraint relation, just taking its derivative wrt time will give you the constraint relation for accelerations)



Q. Give the constraint relations between block A and block B in the setup shown in image alongside 

Solution:

Recall that this trick can only be applied to one string at a time !

So, we take velocity of pulley X as Vx as shown in figure below and we start applying trick from block A end

But, we need relations between Vb and Va




Q. Next Example :

Solution : 

As we discussed, only the velocity component along the string are to be considered

Starting from star (*) mark

Same approach, mark all the points  on the string first

But, we know that the value of Vb (RHS) from the above expression is always going to be positive since 

So, the assumed direction of Vb (upwards) is also correct !


Conclusion :

So, over here, we end this article. Do practice some more string pulley constraint problems using this trick. But also don’t miss out on the actual procedure. Tricks should always be your secondary option !!

 We will keep coming up with more such articles to help you in your preparation !! Thank you for your time.

Have a good day!